2x^2+4x+(3/2)=0

Solution for 2x^2+4x+(3/2)=0 equation:

2x^2+4x+(3/2)=0

We add all the numbers together, and all the variables

2x^2+4x+(+3/2)=0

We get rid of parentheses

2x^2+4x+3/2=0

We multiply all the terms by the denominator


2x^2*2+4x*2+3=0

Wy multiply elements

4x^2+8x+3=0

a = 4; b = 8; c = +3;
Δ = b2-4ac
Δ = 82-4·4·3
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-4}{2*4}=\frac{-12}{8}
=-1+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+4}{2*4}=\frac{-4}{8}
=-1/2
$